The Sblock Elements Ques 20
20. Among $\mathrm{CaH}_2, \mathrm{BeH}_2, \mathrm{BaH}_2$, the order of ionic character is
[2018]
(a) $\mathrm{BeH}_2<\mathrm{CaH}_2<\mathrm{BaH}_2$
(b) $\mathrm{CaH}_2<\mathrm{BeH}_2<\mathrm{BaH}_2$
(d) $\mathrm{BaH}_2<\mathrm{BeH}_2<\mathrm{CaH}_2$
(d) $\mathrm{BeH}_2<\mathrm{BaH}_2<\mathrm{CaH}_2$
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Answer:
Correct Answer: 20.(a)
Solution: (a) $\mathrm{BeH}_2<\mathrm{CaH}_2<\mathrm{BaH}_2$
Smaller the size of cation, more will be its polarising power. Hence, $\mathrm{BeH}_2$ will be least ionic.
BETA
