[2015 RS]
(a) $K_2 CO_3$
(b) $Na_2 CO_3$
(c) $MgCO_3$
(d) $CaCO_3$
Correct Answer: 37.(d)
Solution:
(c) Carbonates becomes more thermally stable down the group, therefore $MgCO_3$ will leave $CO_2$ easily.
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