The Solid State Ques 3
3. A compound is formed by cation $C$ and anion $A$. The anions form hexagonal close packed ( $h c p$ ) lattice and the cations occupy $75 \%$ of octahedral voids. The formula of the compound is:
[2019]
(a) $C_2 A_3$
(c) $C_3 A_4$
(b) $C_3 A_2$
(d) $C_4 A_3$
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Answer:
Correct Answer: 3.(c)
Solution:
(c)
Oh void (C) : $\quad HCP(A)$
$\text{ No. of ions } \Rightarrow 6 \times \frac{75}{100} : 6$
$\hspace{30mm}\frac{3}{4} : 1 $
$\hspace{30mm}3 : 4 \hspace{5mm} C_3 A_4$
BETA
