Alternating Current Ques 40
40. In an ac circuit an alternating voltage e $=200$ $\sqrt{2} \sin 100$ $ t$ volts is connected to a capacitor of capacity $1$ $ \mu F$. The r.m.s. value of the current in the circuit is
[2011]
(a) $10$ $ mA$
(b) $100$ $ mA$
(c) $200$ $ mA$
(d) $20$ $ mA$
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Answer:
Correct Answer: 40.(d)
Solution:
- (d) $V _{rms}=\frac{200 \sqrt{2}}{\sqrt{2}}=200 $ $V$
$I _{rms}=\frac{V _{rms}}{X_C}=\frac{\frac{200}{1}}{100 \times 10^{-6}}$
$=2 \times 10^{-2}=20$ $ mA$