Atoms Ques 10
10. Hydrogen atom in ground state is excited by a monochromatic radiation of $\lambda=975 \mathring {A}$. Number of spectral lines in the resulting spectrum emitted will be
[2014]
3
2
6
10
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Answer:
Correct Answer: 10.(c)
Solution:
- (c) For the $\lambda=975 \mathring{A}$
$ \frac{1}{\lambda}=R(\frac{1}{n_1^{2}}-\frac{1}{n_2^{2}}) $
where $R$ is the Rydberg constant
Solving we get $n_2=n=4$
( $\because n_1=1$ ground state)
Therefore, the number of spectral lines
$=\frac{n(n-1)}{2}=\frac{4(4-1)}{2}=6$
BETA
