Atoms Ques 22
22. The total energy of electron in the ground state of hydrogen atom is $-13.6 eV$. The kinetic energy of an electron in the first excited state is [2007]
(a) $6.8 eV$
(b) $13.6 eV$
(c) $1.7 eV$
(d) $3.4 eV$.
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Answer:
Correct Answer: 22.(d)
Solution:
- (d) Energy in the first excited state
$=\frac{-13.6}{n^{2}}=\frac{-13.6}{2^{2}}=-3.4 eV$
But K.E. $=-($ Total energy $)=+3.4 eV$.
BETA
