Atoms Ques 47
47. The total energy of an electron in an atom in an orbit is $-3.4 eV$. Its kinetic and potential energies are, respectively:
(a) $-3.4 eV,-3.4 eV$
(b) $-3.4 eV,-6.8 eV$
(c) $3.4 eV,-6.8 eV$
(d) $3.4 eV, 3.4 eV$
[2019]
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Answer:
Correct Answer: 47.(c)
Solution:
- (c) According to Bohr’s model of H-atom, the relation between kinetic energy, potential energy and total energy
K.E. $=|TE|=\frac{|P . E .|}{2}$
so, K.E. $=-$ (T.E.)
$\therefore \quad$ K.E. $=3.4 eV$
and P.E. $=2$ (T.E)
$\Rightarrow$ P.E. $=-6.8 eV$