Current Electricity Ques 101
101. A $4 \mu F$ capacitor is charged to 400 volts and then its plates are joined through a resistance of $1 k \Omega$. The heat produced in the resistance is
(a) $0.16 J$
(b) $1.28 J$
(b) $0.64 J$
(d) $0.32 J$
[1994]
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Answer:
Correct Answer: 101.(d)
Solution:
- (d) The energy stored in the capacitor
$ =\frac{1}{2} C V^{2}=\frac{1}{2} \times 4 \times 10^{-4} \times 400 \times 400=0.32 J \text{; } $
This energy will be converted into heat in the resistor.
BETA
