Current Electricity Ques 101

101. A $4 \mu F$ capacitor is charged to 400 volts and then its plates are joined through a resistance of $1 k \Omega$. The heat produced in the resistance is

(a) $0.16 J$

(b) $1.28 J$

(b) $0.64 J$

(d) $0.32 J$

[1994]

Show Answer

Answer:

Correct Answer: 101.(d)

Solution:

  1. (d) The energy stored in the capacitor

$ =\frac{1}{2} C V^{2}=\frac{1}{2} \times 4 \times 10^{-4} \times 400 \times 400=0.32 J \text{; } $

This energy will be converted into heat in the resistor.

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