Current Electricity Ques 46
46. Current through $3 \Omega$ resistor is

46.8 amp., then potential drop through $4 \Omega$ resistor is
(a) $9.6 \mathrm{~V}$
(b) $2.6 \mathrm{~V}$
(c) $4.8 \mathrm{~V}$
(d) $1.2 \mathrm{~V}$
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Answer:
Correct Answer: 46.(c)
Solution:
- (c) Voltage across $3 \Omega$ resistance $=3 \times 0.8=$ 2.4V This voltage is the same across $6 \Omega$ resistance. Hence current through this resistance
$i=\frac{V}{R}=\frac{2.4}{6}=0.4 amp$
Total current in the circuit
$=0.8+0.4=1.2 amp$
Voltage across $4 \Omega$ resistance
$=4 \times 1.2=4.8$ volts