Current Electricity Ques 46

46. Current through $3 \Omega$ resistor is

46.8 amp., then potential drop through $4 \Omega$ resistor is

(a) $9.6 \mathrm{~V}$

(b) $2.6 \mathrm{~V}$

(c) $4.8 \mathrm{~V}$

(d) $1.2 \mathrm{~V}$

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Answer:

Correct Answer: 46.(c)

Solution:

  1. (c) Voltage across $3 \Omega$ resistance $=3 \times 0.8=$ 2.4V This voltage is the same across $6 \Omega$ resistance. Hence current through this resistance

$i=\frac{V}{R}=\frac{2.4}{6}=0.4 amp$

Total current in the circuit

$=0.8+0.4=1.2 amp$

Voltage across $4 \Omega$ resistance

$=4 \times 1.2=4.8$ volts