Current Electricity Ques 68
Two batteries, one of emf 18 V and internal
resistance $2 \Omega$ and the other of emf 12 V and internal resistance $1 \Omega$, are connected as shown. The voltmeter $V$ will record a reading of
[2005]
(a) 30 volt
(b) 18 volt
(c) 15 volts
(d) 14 volt
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Answer:
Correct Answer: 68.(d)
Solution:
(d) $V=\frac{\frac{E_1}{r_1}+\frac{E_2}{r_2}}{\frac{1}{r_1}+\frac{1}{r_2}}=\frac{\frac{18}{2}+\frac{12}{1}}{\frac{1}{2}+\frac{1}{1}}=14 V$
(Since the cells are in parallel).
BETA
