Dual Nature Of Radiation And Matter Ques 16
16. An electron is accelerated through a potential difference of $10,000 $ $V$. Its de Broglie wavelength is, (nearly): $(m_e=9 \times10^{-31} kg)$
[2019]
(a) $12.2 \times 10^{-13} $ $m$
(b) $12.2 \times 10^{-12}$ $ m$
(c) $12.2 \times 10^{-14}$ $ m$
(d) $12.2$ $ nm$
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Answer:
Correct Answer: 16.(b)
Solution:
- (b) de-Broglie wavelength of electron
$ \lambda=\frac{12.27}{\sqrt{V}} \AA=\frac{12.27 \times 10^{-10}}{\sqrt{10000}}=12.27 \times 10^{-12}$ $ m $
BETA
