Dual Nature Of Radiation And Matter Ques 26
26. A source of light is placed at a distance of $50 $ $cm$ from a photocell and the stopping potential is found to be $V_0$. If the distance between the light source and photocell is made $25$ $ cm$, the new stopping potential will be
[NEET Kar. 2013]
(a) $2 V_0$
(b) $V_0 / 2$
(c) $V_0$
(d) $4 V_0$
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Answer:
Correct Answer: 26.(c)
Solution:
- (c) Since, stopping potential is independent of distance hence new stopping potential will remain unchanged i.e., new stopping potential $=V_0$.
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