Dual Nature Of Radiation And Matter Ques 69
69. Momentum of a photon of wavelength $\lambda$ is
[1993]
(a) $\frac{h}{\lambda}$
(b) zero
(c) $\frac{h \lambda}{c^{2}}$
(d) $\frac{h \lambda}{c}$
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Answer:
Correct Answer: 69.(a)
Solution:
- (a) According to de Brogie wave equation,
$ \lambda=\frac{h}{m v}=\frac{h}{p} \quad \therefore p=\frac{h}{\lambda} $
BETA
