Dual Nature Of Radiation And Matter Ques 80
80. If the kinetic energy of the particle is increased to $16 $ times its previous value, the percentage change in the de-Broglie wavelength of the particle is :
[2014]
(a) $25$
(b) $75$
(c) $60$
(d) $50$
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Answer:
Correct Answer: 80.(b)
Solution:
- (b) As we know
$\lambda=\frac{h}{P}=\frac{h}{\sqrt{2 mK}} \quad(\because P=\sqrt{2 mKE})$
or $\frac{\lambda_1}{\lambda_2}=\sqrt{\frac{K_2}{K_1}}=\sqrt{\frac{16 K}{K}}=\frac{4}{1}$
Therefore the percentage change in de-Broglie
wavelength $=\frac{1-4}{4} \times 100=-75 \%$
BETA
