Electric Charges And Fields Ques 14
14. The mean free path of electrons in a metal is $4 \times 10^{-8} m$. The electric field which can give on an average $2 eV$ energy to an electron in the metal will be in units of $V / m$
(a) $5 \times 10^{-11}$
(b) $8 \times 10^{-11}$
(c) $5 \times 10^{7}$
(d) $8 \times 10^{7}$
[2009]
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Answer:
Correct Answer: 14.(c)
Solution:
- (c) Energy $=2 eV$
$\Rightarrow eV_o=2 eV \Rightarrow V_o=2$ volt
$ \begin{aligned} E & =\frac{V_O}{d}=\frac{2}{4 \times 10^{-8}} \\ & =0.5 \times 10^{8}=5 \times 10^{7} Vm^{-1} \end{aligned} $
BETA
