Electromagnetic Induction Ques 13
13. A cycle wheel of radius $0.5 $ $m$ is rotated with constant angular velocity of $10$ $ rad / s$ in a region of magnetic field of $0.1$ $ T$ which is perpendicular to the plane of the wheel. The EMF generated between its centre and the rim is
[NEET Odisha 2019]
(a) zero
(b) $0.25 $ $V$
(c) $0.125$ $ V$
(d) $0.5 $ $V$
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Answer:
Correct Answer: 13.(c)
Solution:
- (c) Using Faraday’s law,
$e=\frac{B l^{2} \omega}{2}=\frac{1}{2} \times 0.1 \times(\frac{1}{2})^{2} \times 10=\frac{1}{8}=0.125 $ $V$
BETA
