Electromagnetic Induction Ques 14
14. The magnetic potential energy stored in a certain inductor is $25$ $ mJ$, when the current in the inductor is $60 $ $mA$. This inductor is of inductance
[2018]
(a) $0.138 $ $H$
(b) $138.88 $ $H$
(c) $13.89 $ $H$
(d) $1.389 $ $H$
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Answer:
Correct Answer: 14.(c)
Solution:
- (c) From question energy stored in inductor, $U=25 \times 10^{-3} J$
Current, $I=60$ $ mA$
Energy stored in inductor $U=\frac{1}{2} L I^{2}$
$25 \times 10^{-3}=\frac{1}{2} \times L \times(60 \times 10^{-3})^{2}$
$L=\frac{25 \times 2 \times 10^{6} \times 10^{-3}}{3600}=13.89$ $ H$
BETA
