Electromagnetic Induction Ques 20
20. Two coils have a mutual inductance $0.005 $ $H$. The current changes in the first coil according to equation $I=I_0 \sin \omega t$, where $I_0=10 $ $A$ and $\omega=100 $ $\pi $ $radian / sec$. The maximum value of e.m.f. in the second coil is
[1998]]
(a) $2 p$
(b) $5 p$
(c) $p$
(d) $4 p$
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Answer:
Correct Answer: 20.(b)
Solution:
- (b) $e=-M \frac{d i}{d t}=-0.005 \times \frac{d(i_0 \sin \omega t)}{dt}$
$ =-0.005 \times i_0 \times(\omega \cos \omega t) $
$e _{\text{max }}=0.005 \times i_0 \times \omega($ when $\cos \omega t=-1)$
$ =0.005 \times 10 \times 100 \pi=5 \pi$ $ V $
BETA
