Electromagnetic Induction Ques 21
21. A conductor of length $0.4 $ $m$ is moving with a speed of $7 $ $m / s$ perpendicular to a magnetic field of intensity $0.9 $ $Wb / m^{2}$. The induced e.m.f. across the conductor is
[1995]
(a) $1.26 $ $V$
(b) $2.52 $ $V$
(c) $5.04 $ $V$
(d) $25.2 $ $V$
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Answer:
Correct Answer: 21.(b)
Solution:
- (b) Length of conductor $(l)=0.4 $ $m$;
Speed (v) $=7 $ $m / s$ and magnetic field $(B)=0.9 $ $Wb / m^{2}$.
Induced e.m.f. $(V)=B l v \sin \theta=0.9 \times 0.4 \times 7 \times \sin$ $90^{\circ}=2.52 $ $V$.
BETA
