Electromagnetic Induction Ques 37
37. In a coil of resistance $10$ $ \Omega$, the induced current developed by changing magnetic flux through it, is shown in figure as a function of time. The magnitude of change in flux through the coil in Weber is :
[2012M]
(a) $8$
(b) $2$
(c) $6$
(d) $4$
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Answer:
Correct Answer: 37.(b)
Solution:
- (b) The charge through the coil $=$ area of current-time $(i-t)$ graph
$q=\frac{1}{2} \times 0.1 \times 4=0.2 $ $C$
$q=\frac{\Delta \phi}{R} \quad \because$ Change in flux $(\Delta \phi)=q \times R$
$q=0.2=\frac{\Delta \phi}{10}$
$\Delta \phi=2$ Weber
BETA
