Electrostatic Potential And Capacitance Ques 14
14. A short electric dipole has a dipole moment of $16 \times 10^{-9}$ $ C m$. The electric potential due to the dipole at a point at a distance of $0.6 $ $m$ from the centre of the dipole, situated on a line making an angle of $60^{\circ}$ with the dipole axis is : $(\frac{1}{4 \pi \epsilon_0}=9 \times 10^{9} $ $Nm^{2} / C^{2})$
[2020]
(a) $200 $ $V$
(b) $400 $ $V$
(c) zero
(d) $50$ $ V$
Show Answer
Answer:
Correct Answer: 14.(a)
Solution:
- (a) Given,
Dipole moment of short electric dipole,
$p=16 \times 10^{-9}$ $ Cm$.
Distance from centre of dipole, $r=0.6 $ $m$
Electric potential, $V=\frac{k p \cos \theta}{r^{2}}$
$\Rightarrow V=\frac{9 \times 10^{9} \times 16 \times 10^{-9} \times \cos 60}{0.36}=200$ $ V$
BETA
