Electrostatic Potential And Capacitance Ques 29
29. Three capacitors each of capacitance $C$ and of breakdown voltage $V$ are joined in series. The capacitance and breakdown voltage of the combination will be
[2009]
(a) $3 $ $C, \frac{V}{3}$
(b) $\frac{C}{3}, 3$ $ V$
(c) $3\ \text{C}, 3\ \text{V}$
(d) $\frac{C}{3}, \frac{V}{3}$
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Answer:
Correct Answer: 29.(b)
Solution:
- (b) In series combination of capacitors, the total capacitance is less than the smallest individual capacitance.
$V _{\text{eff }}=V+V+V=3V$
$\frac{1}{C _{eff}}=\frac{1}{C}+\frac{1}{C}+\frac{1}{C}$
$\Rightarrow C _{eff}=\frac{C}{3}$
Thus, the capacitance and breakdown voltage of the combination will be $\frac{C}{3}$ and $3V$.
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