Electrostatic Potential And Capacitance Ques 33
33. Three capacitors each of capacity $4 $ $\mu F$ are to be connected in such a way that the effective capacitance is $6 $ $\mu F$. This can be done by
[2003]
(a) connecting two in parallel and one in series
(b) connecting all of them in series
(c) connecting them in parallel
(d) connecting two in series and one in parallel
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Answer:
Correct Answer: 33.(d)
Solution:
- (d) For series, $C^{\prime}=\frac{C_1 \times C_2}{C_1+C_2}=\frac{4 \times 4}{4+4}=2 $ $\mu F$
For parallel, $C _{eq}=C^{\prime}+C_3=2+4=6 $ $\mu F$
If $C_P$ is the effective capacity when $n$ identical capacitors are connected in parallel and $C_s$ is their effective capacity when connected in series then $\frac{C_p}{C_s}=n^{2}$
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