Gravitation Ques 58
58. If the gravitational force between two objects were proportional to $1 / R$ (and not as $1 / R^{2}$ ) where $R$ is separation between them, then a particle in circular orbit under such a force would have its orbital speed $v$ proportional to
[1989]
(a) $1 / R^{2}$
(b) $R^{0}$
(c) $R^{1}$
(d) $1 / R$
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Answer:
Correct Answer: 58.(b)
Solution:
- (b) $F=\frac{k}{R}=\frac{M v^{2}}{R}$. Hence $v \propto R^{0}$
BETA
