Gravitation Ques 59
59. For a satellite escape velocity is $11$ $ km / s$. If the satellite is launched at an angle of $60^{\circ}$ with the vertical, then escape velocity will be
[1989]
(a) $11$ $ km / s$
(b) $11 \sqrt{3} $ $km / s$
(c) $\frac{11}{\sqrt{3}}$ $ km / s$
(d) $33 $ $km / s$
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Answer:
Correct Answer: 59.(a)
Solution:
- (a) Since, escape velocity $(v_e=\sqrt{2 g R_e})$ is independent of angle of projection, so it will not change.
BETA
