Kinetic Theory Ques 33
33. A polyatomic gas with $n$ degrees of freedom has a mean energy per molecule given by
[1989]
(a) $\frac{n k T}{N}$
(b) $\frac{n k T}{2 N}$
(c) $\frac{n k T}{2}$
(d) $\frac{3 k T}{2}$
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Answer:
Correct Answer: 33.(c)
Solution:
- (c) According to law of equipartition of energy, the energy per degree of freedom is $\frac{1}{2}$ $ k T$.
For a polyatomic gas with $n$ degrees of freedom, the mean energy per molecule $=\frac{1}{2} $ $n k T$
BETA
