Laws Of Motion Ques 13
13. A satellite in a force free space sweeps stationary interplanetary dust at a rate $(dM / dt)=\alpha v$. The acceleration of satellite is
[1994]
(a) $\frac{-2 \alpha v^{2}}{M}$
(b) $\frac{-\alpha v^{2}}{M}$
(c) $\frac{-\alpha v^{2}}{2 M}$
(d) $-\alpha v^{2}$
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Answer:
Correct Answer: 13.(b)
Solution:
- (b) Thrust on the satellite,
$F=\frac{-v d M}{d t}=-v(\alpha v)=-\alpha v^{2}$
Acceleration $=\frac{F}{M}=\frac{-\alpha v^{2}}{M}$
BETA
