Laws Of Motion Ques 16
16. A particle of mass $m$ is moving with a uniform velocity $v_1$. It is given an impulse such that its velocity becomes $v_2$. The impulse is equal to
[1990]
(a) $m[|v_2|-|v_1|]$
(b) $\frac{1}{2} m[v_2{ }^{2}-v_1{ }^{2}]$
(c) $m[v_1+v_2]$
(d) $m[v_2-v_1]$
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Answer:
Correct Answer: 16.(d)
Solution:
- (d) Impulse $=$ final momentum - initial momentum $=m(v_2-v_1)$
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