Laws Of Motion Ques 3
3. The coefficient of static friction, $\mu_s$, between block A of mass $2 $ $\mathrm{kg}$ and the table as shown in the figure is $0.2$ . What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless.
$(g= 10 $ $m/s^2)$
(a) $0.4$ $ \mathrm{kg}$
(b) $2.0 $ $\mathrm{kg}$
(c) $4.0 $ $\mathrm{kg}$
(d) $0.2 $ $\mathrm{kg}$
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Answer:
Correct Answer: 3.(a)
Solution: (a) Condition for the max value of mass of block $B$ so that two blocks do not move is,
$ \begin{aligned} & m_B g=\mu_s m_A g \\ & \Rightarrow m_B=\mu_s m_A \\ & \text { or, } m_B=0.2 \times 2=0.4 \mathrm{kg} \end{aligned} $
BETA
