Laws Of Motion Ques 31
31. A man weighing $80 kg$, stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $5 m / s^{2}$. What would be the reading on the scale? $(g=10 m / s^{2})$ [2003]
(a) $1200 N$
(b) zero
(c) $400 N$
(d) $800 N$
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Answer:
Correct Answer: 31.(a)
Solution:
- (a) Reading of the scale = Apparent wt. of the man $=m(g+a)$ $=80(10+5)=1200 N$
BETA
