Laws Of Motion Ques 47
47. A $100 N$ force acts horizontally on a block of $10 kg$ placed on a horizontal rough surface of coefficient of friction $\mu=0.5$. If the acceleration due to gravity $(g)$ is taken as 10 $ms^{-2}$, the acceleration of the block (in $ms^{-2}$ ) is
(a) 2.5
(b) 10
(c) 5
(d) 7.5
[2002]
Show Answer
Answer:
Correct Answer: 47.(c)
Solution:
(c) $a=\frac{F-\mu R}{m}=\frac{100-0.5 \times(10 \times 10)}{10}=5 ms^{-2}$
BETA
