Laws Of Motion Ques 63
63. A car of mass $m$ is moving on a level circular track of radius $R$. If $\mu_s$ represents the static friction between the road and tyres of the car, the maximum speed of the car in circular motion is given by :
[2012M]
(a) $\sqrt{\mu_s m R g}$
(b) $\sqrt{R g / \mu_s}$
(c) $\sqrt{m R g / \mu_s}$
(d) $\sqrt{\mu_s R g}$
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Answer:
Correct Answer: 63.(d)
Solution:
- (d) For smooth driving maximum speed of car $v$ then,
$ \begin{aligned} & \frac{m v^{2}}{R}=\mu_s m g \\ & v=\sqrt{\mu_s R g} \end{aligned} $
BETA
