Motion In A Plane Ques 20

20. A particle starting from the origin $(0,0)$ moves in the $(x, y)$ plane. Its coordinates at a later time are $(\sqrt{3}, 3)$. The path of the particle makes with the $x$-axis an angle of

[2007]

(a) $45^{\circ}$

(b) $60^{\circ}$

(c) $0^{\circ}$

(d) $30^{\circ}$

Show Answer

Answer:

Correct Answer: 20.(b)

Solution:

  1. (b)

Let $\theta$ be the angle which the particle makes with $x$-axis.

From figure, $\tan \theta=\frac{3}{\sqrt{3}}=\sqrt{3}$

$\Rightarrow \theta=\tan ^{-1}(\sqrt{3})=60^{\circ}$

If a vector $\vec{R}$ in $X-Y$ plane then its orthogonal vector $R_X=R \cos \theta$ and $R_Y=R \sin \theta$.

$ \text{ And } \frac{R \sin \theta}{R \cos \theta}=\tan \theta=\frac{R_Y}{R_X} $



sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! ЁЯМРЁЯУЪЁЯЪАЁЯОУ

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language
рдХреГрдкрдпрд╛ рдЕрдкрдиреА рдкрд╕рдВрджреАрджрд╛ рднрд╛рд╖рд╛ рдЪреБрдиреЗрдВ