Moving Charges And Magnetism Ques 26
26. Two toroids $1$ and $2$ have total no. of turns $200$ and $100$ respectively with average radii $40 $ $cm$ and $20$ $ cm$ respectively. If they carry same current $i$, the ratio of the magnetic fields along the two loops is,
(a) $1: 2$
(b) $1: 1$
(c) $4: 1$
(d) $2: 1$
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Answer:
Correct Answer: 26.(b)
Solution:
- (b) $B=\frac{\mu_0 N \cdot I}{2 \pi R}$
$\therefore \quad \frac{B_1}{B_2}=\frac{N_1 R_2}{N_2 R_1}=\frac{200}{100} \frac{20}{40}=1$
So, $\frac{B_1}{B_2}=1$
BETA
