Moving Charges And Magnetism Ques 86
86. A galvanometer of resistance $20$ $ \Omega$ gives full scale deflection with a current of $0.004$ $ A$. To convert it into an ammeter of range $1$ $ A$, the required shunt resistance should be
[1996]
(a) $0.38$ $ \Omega$
(b) $0.21$ $ \Omega$
(c) $0.08$ $ \Omega$
(d) $0.05$ $ \Omega$
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Answer:
Correct Answer: 86.(c)
Solution:
- (c) Maximum current which can pass through galvanometer, $I_g=0.004 $ $A$
Let $R$ be the resistance of shunt.
We know potential drop across $A B$
$=$ Potential drop across $C D$
$R(I-I_g)=I_g(20)$
$\Rightarrow R(1-0.004)=0.004 \times 20 \Rightarrow R=0.08 $ $\Omega$
BETA
