Nuclei Ques 14
14. The ratio of the radii of the nuclei $ _{13} A l^{27}$ and $ _{52} Te^{125}$ is approximately
[1990]
(a) $6: 10$
(b) $13: 52$
(c) $40: 177$
(d) $14: 73$
Show Answer
Answer:
Correct Answer: 14.(a)
Solution:
(a) $R \propto(A)^{1 / 3}$
$\therefore R _{A l} \propto(27)^{1 / 3}$ and $R _{T e} \propto(125)^{1 / 3}$
$\therefore \frac{R _{A l}}{R _{T e}}=\frac{3}{5}=\frac{6}{10}$
BETA
