Nuclei Ques 21
21. A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 a.m.u. The energy liberated per a.m.u. is
(Given : 1 a.m.u = $931 MeV$ )
[2013]
(a) $26.7 MeV$
(b) $6.675 MeV$
(c) $13.35 MeV$
(d) $2.67 MeV$
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Answer:
Correct Answer: 21.(b)
Solution:
- (b) Mass defect $\Delta m=0.02866$ a.m.u.
Energy $=0.02866 \times 931=26.7 MeV$
As $ _1 H^{1}+ _1 H^{1} \longrightarrow _2 He^{4}$
Energy liberated per a.m.u $=13.35 / 2 MeV$
$=6.675 MeV$
BETA
