Nuclei Ques 47
47. If the binding energy per nucleon in $ _3 Li^{7}$ and $ _2 He^{4}$ nuclei are respectively $5.60 MeV$ and 7.06
$MeV$, then the energy of proton in the reaction
$ _3 Li^{7}+p \to 2 _2 He^{4}$ is
[1994]
(a) $19.6 MeV$
(b) $2.4 MeV$
(c) $8.4 MeV$
(d) $17.3 MeV$
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Answer:
Correct Answer: 47.(d)
Solution:
- (d) Applying principle of energy conservation, Energy of proton
$=$ total B.E. of $2 \alpha-$ energy of $Li^{7}$
$=8 \times 7.06-7 \times 5.6$
$=56.48-39.2=17.28 MeV$
BETA
