Oscillations Ques 35
35. A pendulum is hung from the roof of a sufficiently high building and is moving freely to and from like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20$ $m / s^{2}$ at a distance of $5$ $ m$ from the mean position. The time period of oscillation is
[2018]
(a) $2 \pi $ $s$
(b) $\pi $ $s$
(c) $1 $ $s$
(d) $2 $ $s$
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Answer:
Correct Answer: 35.(b)
Solution:
- (b) From question, acceleration, $a=20$ $ m / s^{2}$, and displacement, $y=5$ $ m$
$ |a|=\omega^{2} y $
$\Rightarrow 20=\omega^{2}(5)$
$\Rightarrow \omega=2 $ $rad / s$
Time period of pendulum,
$ T=\frac{2 \pi}{\omega}=\frac{2 \pi}{2}=\pi s $
BETA
