Oscillations Ques 54
54. The time period of a simple pendulum is $2$ seconds. If its length is increased by $4$-times, then its period becomes
[1999]
(a) $16 $ $s$
(b) $12 $ $s$
(c) $8 $ $s$
(d) $4 $ $s$
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Answer:
Correct Answer: 54.(d)
Solution:
- (d) $T=2 \pi \sqrt{\frac{\ell}{g}} \quad T \propto \sqrt{\ell}$
If $\ell$ is increased by $4$ times, time period will increase by two times.
BETA
