[2001]
(a) energy
(b) power
(c) momentum
(d) angular momentum
Correct Answer: 15.(d)
Solution:
$h=\frac{E}{v}=\frac{[ML^{2} T^{-2}]}{[T^{-1}]}=[ML^{2} T^{-1}]$
Angular momentum $=I \omega$
$=[ML^{2}][T^{-1}]=[ML^{2} T^{-1}]$
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