Physical World Units And Measurements Ques 24
24. The dimensional formula for permeability $\mu$ is given by $[M^1 L^0 T^{-2} A^2]$
[1991]
(a) $[MLT^{-2} A^{-2}]$
(b) $[M^{0} L^{1} T^{-1}]$
(c) $[M^{0} L^{2} T^{-1} A^{2}]$
(d) None of the above
Show Answer
Answer:
Correct Answer: 24.(a)
Solution:
- (a) Permeability of free space,
$ \mu_0=\frac{2 \pi \times \text{ force } \times \text{ distance }}{(\text{ current })^{2} \times \text{ length }} $
So, dimensional formulae
$ \mu_0=\frac{[MLT^{-2}][L]}{[A^{2}][L]}=[MLT^{-2} A^{-2}] $
Also find the dimensional formula by using the relation,
Speed of light, $c=\frac{1}{\sqrt{\mu_0 \varepsilon_0}}$
BETA
