Physical World Units And Measurements Ques 37
37. A screw gauge has least count of $0.01$ $ mm$ and there are $50$ divisions in its circular scale. The pitch of the screw gauge is :
[2020]
(a) $0.25 $ $mm$
(b) $0.5 $ $mm$
(c) $1.0 $ $mm$
(d) $0.01 $ $mm$
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Answer:
Correct Answer: 37.(b)
Solution:
- (b) Least count of screw gauge $=0.01$ $ mm$ Least count
$= \frac{\text{Pitch}}{\text{ No. of divisions on circular scale} }$
$\Rightarrow 0.01$ $ mm=\frac{\text{ Pitch }}{50}$
$\Rightarrow$ Pitch $=0.5 $ $mm$
BETA
