Ray Optics And Optical Instruments Ques 64
64. Angle of deviation ( $\delta$ ) by a prism (refractive index $=\mu$ and supposing the angle of prism A to be small) can be given by
[1994]
(a) $\delta=(\mu-1) \lambda$
(b) $\delta=(\mu+1) \cdot A$
(c)$\delta=\frac{\sin \frac{A+\delta}{2}}{\sin \frac{A}{2}}$
(d) $\delta=\frac{\mu-1}{\mu+1} A$
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Answer:
Correct Answer: 64.(a)
Solution:
- (a) When the angle of prism is small, $\delta=(\mu-1) A$
BETA
