Semiconductor Electronics Materials Devices And Simple Circuits Ques 6

6. In the following circuit, the output $Y$ for all possible inputs $A$ and $B$ is expressed by the truth table

[2007]

(a) $A \quad B \quad Y$

$\begin{matrix} \quad 0 & 1 & 1\end{matrix} $

$\begin{matrix} \quad 0 & 1 & 1\end{matrix} $

$\begin{matrix} \quad 1 & 0 & 1\end{matrix} $

$\begin{matrix}\quad 1 & 1 & 0\end{matrix} $

(b) $\begin{matrix} A & B & Y\end{matrix} $

$\begin{matrix} \quad 0 & 0 & 1\end{matrix} $

$\begin{matrix} \quad 0 & 1 & 1\end{matrix} $

$\begin{matrix} \quad 1 & 0 & 0\end{matrix} $

$\begin{matrix} \quad 1 & 1 & 0\end{matrix} $

(c) $\begin{matrix} A & B & Y\end{matrix} $

$\begin{matrix} \quad 0 & 0 & 0\end{matrix} $

$\begin{matrix} \quad 0 & 1 & 1\end{matrix} $

$\begin{matrix} \quad 1 & 0 & 1\end{matrix} $

$\begin{matrix} \quad 1 & 1 & 1\end{matrix} $

(d) $\begin{matrix} A & B & Y\end{matrix} $

$\begin{matrix} \quad 0 & 0 & 0\end{matrix} $

$\begin{matrix} \quad 0 & 1 & 0\end{matrix} $

$\begin{matrix} \quad 1 & 0 & 0\end{matrix} $

$\begin{matrix} \quad 1 & 1 & 1\end{matrix} $

Show Answer

Answer:

Correct Answer: 6.(c)

Solution:

  1. (c)

$Y^{\prime}=\overline{A+B} ; Y=\overline{\overline{A+B}}=A+B$

Therefore truth table:

$A$$B$$Y$
000
011
101
111


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