System Of Particles And Rotational Motion Ques 16
16. The angular speed of an engine wheel making $90 $ revolutions per minute is
[1995]
(a) $1.5 \pi$ $ rad / s$
(b) $3 \pi$ $ rad / s$
(c) $4.5 \pi$ $ rad / s$
(d) $6 \pi$ $ rad / s$
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Answer:
Correct Answer: 16.(b)
Solution:
- (b) Number of revolutions made by the engine wheel $(n)=90$ per minute.
Angular speed of the engine wheel
$(\omega)=\frac{2 \pi n}{60}=\frac{2 \pi \times 90}{60}=3 \pi$ $ rad / s$.
BETA
