System Of Particles And Rotational Motion Ques 47
47. A constant torque of $1000 $ $N-m$ turns a wheel of moment of inertia $200$ $ kg-m^{2}$ about an axis through its centre. Its angular velocity after $3$ seconds is
[2001]
(a) $1$ $ rad / s$
(b) $5$ $ rad / s$
(c) $10$ $ rad / s$
(d) $15$ $ rad / s$
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Answer:
Correct Answer: 47.(d)
Solution:
- (d) $\tau=1000$ $ N-m, I=200 $ $kg-m^{2}$
$\tau=I . \alpha$ and $\alpha=(\frac{\omega_f-\omega_0}{t})$
$\Rightarrow \alpha=\frac{1000}{200}=5$ $ rad / sec^{2}$
$\omega_1=\omega_0+\alpha t=0+3 \times 5=15$ $ rad / s$
BETA
