System Of Particles And Rotational Motion Ques 60
60. The moment of inertia of a thin uniform rod of mass $M$ and length $L$ about an axis passing through its midpoint and perpendicular to its length is $I_0$. Its moment of inertia about an axis passing through one of its ends and perpendicular to its length is
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(a) $I_0+ML^{2} / 2$
(b) $I_0+ML^{2} / 4$
(c) $I_0+2 ML^{2}$
(d) $I_0+ML^{2}$
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Answer:
Correct Answer: 60.(b)
Solution:
- (b) By theorem of parallel axes,
$I=I _{cm}+Md^{2}$
$I=I_0+M(L / 2)^{2}=I_0+ML^{2} / 4$
BETA
