System Of Particles And Rotational Motion Ques 9
9. In carbon monoxide molecule, the carbon and the oxygen atoms are separated by a distance $1.12 \times 10^{-10}$ $ m$. The distance of the centre of mass, from the carbon atom is
[1997]
(a) $0.64 \times 10^{-10} $ $m$
(b) $0.56 \times 10^{-10} $ $m$
(c) $0.51 \times 10^{-10} $ $m$
(d) $0.48 \times 10^{-10} $ $m$
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Answer:
Correct Answer: 9.(a)
Solution:
From definition of centre of mass.
$ \begin{aligned} d & =\frac{16 \times 1.12 \times 10^{-10}+12 \times 0}{16+12} \\ & =\frac{16 \times 1.12 \times 10^{-10}}{28}=0.64 \times 10^{-10} m . \end{aligned} $
BETA
