System Of Particles And Rotational Motion Ques 90
90. The speed of a homogenous solid sphere after rolling down an inclined plane of vertical height $h$ from rest without sliding is
[1992]
(a) $\sqrt{\frac{10}{7} g h}$
(b) $\sqrt{g h}$
(c) $\sqrt{\frac{6}{5} g h}$
(d) $\sqrt{\frac{4}{3} g h}$
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Answer:
Correct Answer: 90.(a)
Solution:
- (a) P.E. $=$ total $K.E.$
$mgh = \frac{7}{10}mv^2,$
$\therefore$ $v = \sqrt{\frac{10gh}{7}}$
BETA
